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Author:王博賢

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柱體建築師
【案例】2013年安徽高考15题
判斷球體
球體建築師
兩組對邊相等和有直角的四邊形

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折紙畫橢圓
扇形面積公式
(004)80201辛宇婕
单晨答河北代军辉-动态序列文本逐行体现
S0G5平均不等式（无字证明）

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Quadrilaterals
Linear Equations
Cosine
Addition
Rhombus

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