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Borsuk Problem in 2 Dimensions (Latter Trial)
Forfatter
beryakuru
∠KBI = ∠KBJ = 30°. K = (B + I + J)/3. Therefore, BI = BJ = IJ.
GeoGebra
Nye Materialer
Cosine in Cartesian and Polar Coordinates
functionartculture
Hypocycloids
גיליון אלקטרוני להעלאת נתוני בעיה ויצירת גרף בהתאם
Graphing 1 + cos(θ) in Polar Coordinates
Opdag Ressourcer
TT 1A1 TT 1A1
Cooper - Rocket
Three trig graphs
course chien
Paco - Tschirnhaus's cubic
Udforsk emner
Randomiserede variables
Statistik
Parametriske Kurver
Trigonometriske funktioner
Firkanter