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難問1A
Author:
Bunryu Kamimura
よって、△BEHは直角二等辺三角形になる。
GeoGebra
New Resources
standingwave
平均変化率
目で見る立方体の2等分
standingwave-reflection-free
小テスト
Discover Resources
キーペルト点と刈屋点
Graphs of Resistors in Circuits
傍心三角形⇔垂足三角形
safig1
立方体の切断面
Discover Topics
Pie Chart or Circle Chart
Median Value
Similar Triangles
Difference and Slope
Geometric Mean