i / i^2 - Hyperbola
Look how nicely this all works out - see - a = 4 -: Click in input box to right of value - backspace - type in new value
1) Area(k) of the Triangle = 1.64
2) Area of Quarter Circle - Triangle = 1 - Notice how this difference obtains integer values very nicely and regularly...
3) Notice t(x) Brown equation = 1 / i / i^2