Parrallelogram1514

Author:
650529
I first drew segment AB and made two circles at each endpoint. I then drew segment CD and EF to make a perpendicular bisector, and I drew segment GH with two circles at each endpoint. I then drew segments MD, PQ, IL, and NR and points J and K. Triangles BQA and HAB are congruent due to AB=AB(reflexive), BQ=AH(radii), and angles ABQ=BAH(perpendicular to the same line) completing the congruence theorem SAS. HA and BQ are congruent due to CPCTC, and parallel because they are perpendicular to the same line. AQ and HB are congruent due to CPCTC, and parallel because segment MD, the perpendicular bisector, runs through them.