Solution to the game with three circles.

Autor:Doru Paunescu

Three blue circles with the same radius R meets two by two in A1, A2 respectively in A3. The red circle circumscribed to the triangle A1A2A3 has the same radius R iff the blue circles have a common point.

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Fără titlu
Teorema celor trei perpendiculare - Aplicația 2

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Cálculo diferencial
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Secciones Cónicas
Sustracción
Fractales