Bernoulli Distribution - Defining 'p'
- Author:
- RV'SMath
1) This is where it all started:
2) This shows how I now have calculated what 'p' equals: So to obtain Integers with the expression below.
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When integrating the Integral 2^p(1-p) must be integrated in terms of 'x': 2^x(1-x) = 2.53