First I drew segment AC and then made 2 circles at each endpoint. I added 2 points and made line DE through them. Then, I drew Circle B,DC,AE,EC, and AD.Circle C has the same radius as Circle A and the line DE is the perpendicular to line AC(the radius). AB=BC=DB=BE because of the perpendicular bisector and because they are the radius of Circle B. Triangle ABD is isosceles and m<ABD=90 degrees, so the bases angles must equal 45 degrees which makes angle CDA,DAE,DCE, and CEA all 90 degrees. Knowing this makes all of the triangles congruent because of SSA.